Question

Sum and product of the zeroes of polynomial x²-3 are respectively​

Answer 1

Step-by-step explanation:

$\star{ \pink{ \bf{ \underline{ \underline{solution \: : - }}}}}$

$\bf{ \ {x}^{2} - 3}$

$\implies{ \bf{ {x}^{2} = 3}}$

$\implies{ \bf{ x = \sqrt{3}}}$

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So,

zero of polynomial

$\bf{ x = + \sqrt{3} } \: \: and \: \bf{x = - \sqrt{3} }$

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Sum of polynomial:-

$\bf{ + \sqrt{3} + ( - \sqrt{3})}$

$\bf{ \cancel{ = \sqrt{3} - \sqrt{3}}}$

$= \bf{0}$

$\boxed{ \frac{ - (x \: product)}{ {x}^{2} \: product} }$

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Products of polynomial,

$\bf{ (\sqrt{3}) \: (\sqrt{ - 3})}$

$\bf{ = - 3}$

$\boxed{ \bf{ \frac{constant}{ {x}^{2} \: product}}}$

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