Question

WILL MARK AS BRAINLIEST

Answer 1

Answer:

46 units

Step-by-step explanation:

Answer attached above....

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Answer 2

Answer:

Given,

VU=9un

Let us assume (9,6) as point A

In Triangle TUA

TA=4un

UA=3un

$(UT)^2=(TA)^2+(UA)^2$

$UT^2=(4)^2+(3)^2$

$UT^2=16+9$

$UT^2=25\\UT=\sqrt{25}\\UT=5un$

Let us assume (5,-9) as point B

In triangle formed by AST,

AS=8un

TA=15un

$(TS)^2=(AS)^2+(TA)^2\\TS^2=(8)^2+(15)^2\\TS^2=64+225\\TS^2=289\\TS=\sqrt{289}\\TS=17un$

Let us assume (9,-9) as point C

In Triangle formed by CSV,

CS=12un

VC=9un

$(VS)^2=(CS)^2+(VC)^2$

$VS^2=(12)^2+(9)^2$

$VS^2=144+81$

$VS^2=225$

$VS=\sqrt{225}$

$VS=15un$

All the sides of the quadrilateral are:-

VU=9un

UT=5un

TS=17un

VS=15un

Perimeter=sum of all sides,

=VU+UT+TS+VS

=9+5+17+15

=46un

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i gave with full explanation