sum of 1+(1+2)+(1+2+3)+............+(1+2+3+..........17) is :
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Hey mate here is your answer...
hope it helps you..
hope it helps you..
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Saugata001:
bhag. it is not the answer. Foolish guy
wt happened
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Since sum of series:- 1+2+3+...n times is n(n+1)/2
=>1(1+1)/2+2(2+1)/2+3(3+1)/2+........+17(17+1)/2
=>(1(1+1)+2(2+1)+3(3+1)+.....+17(17+1))/2
=>((1^2+2^2+3^2+...17^2)+(1+2+3+...+17))/2
=>((17(17+1)(2*17+1))/6)+(17(17+1))/2))/2
=>((17*18*35)/6)+(18*17)/2)/2
=>(1785+153)/2
=>969
Hope it helps u!!
thank u
=>1(1+1)/2+2(2+1)/2+3(3+1)/2+........+17(17+1)/2
=>(1(1+1)+2(2+1)+3(3+1)+.....+17(17+1))/2
=>((1^2+2^2+3^2+...17^2)+(1+2+3+...+17))/2
=>((17(17+1)(2*17+1))/6)+(17(17+1))/2))/2
=>((17*18*35)/6)+(18*17)/2)/2
=>(1785+153)/2
=>969
Hope it helps u!!
thank u
285
use this method and solve it
ok
Ok thanx
bro your ans is wrong
285 is not correct
directly thoda soch k dekho uska sum utna aa hi ni skta
last k 2 sums ka sum hi 289 ho rha to total 285 kaise ho skta
1+3+..... And not 1+2+..... iye socho bhao
kya matlab
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