Question

Sum of 2 positive integers is 34 and their difference is 8,find their product

Answer 1

Refer the attachment.

Answer 2

Their product  is 273

Step-by-step explanation:

Let the two positive integers be x and y

Sum of 2 positive integers is 34

$x+y=34$ ---- 1

Their difference is 8

$x-y=8$ ---2

Add 1 and 2

$x+y+x-y=34+8$

$2x=42$

$x=\frac{42}{2}$

$x=21$

Substitute the value in 1

$21+y=34$

$y=13$

So, Two integers are 21 and 13

Product of these integers =$21 \times 13 =273$

Hence their product  is 273

#Learn more:

The sum of 2 integers is -47.if one of integer is -34 is find the other ​

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