in the infrared region of the atomic spectrum of hydrogen a line is obtained at 3802 cm^1. calculate energy? PLZZZZ ANS FAST TOMORROW EXAM OF MINE.... PLZZZZZ...
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Answered by
73
We know that ,
Frequency(v) can be calculated as follows:
λv = c
where λ = 3802 x 10-2 m
c = 3 x 108 m/s
Frequency, v = (3 x 108 m/s) / 3802 x 10-2m
= 7.89 x 106 s-1
Energy = hv
where h = 6.626 x 10-34 J/s
Hence, energy of the photon
= 6.626 x 10-34 J/s x 7.89 x 106 s-1
= 52.279 x 10-28 J
Frequency(v) can be calculated as follows:
λv = c
where λ = 3802 x 10-2 m
c = 3 x 108 m/s
Frequency, v = (3 x 108 m/s) / 3802 x 10-2m
= 7.89 x 106 s-1
Energy = hv
where h = 6.626 x 10-34 J/s
Hence, energy of the photon
= 6.626 x 10-34 J/s x 7.89 x 106 s-1
= 52.279 x 10-28 J
Answered by
6
Answer:
We know that ,
Frequency(v) can be calculated as follows:
λv = c
where λ = 3802 x 10-2 m
c = 3 x 108 m/s
Frequency, v = (3 x 108 m/s) / 3802 x 10-2m
= 7.89 x 106 s-1
Energy = hv
where h = 6.626 x 10-34 J/s
Hence, energy of the photon
= 6.626 x 10-34 J/s x 7.89 x 106 s-1
= 52.279 x 10-28 J
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