sum of 25 terms of sequence 11,15,19...327
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Step-by-step explanation:
sum of terms =n/2(2a+(n-1)d
_ n already given 25
=25/2(2(11)+(25-1)4
=12.5(22+24(4))
=12.5(22+96)
=12.5(118)
=147.5 this is sum of n terms formulae
and also
=a+(n-1)d
=11+(25-1)4
=11+24×4
11+96
=107
it is the arthematic progression formula in series
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