Question

Sum of 3 numbers in arthematic progressions is 39 and and their product is 2184 find them ​

Answer 1

Answer:

12,13,14

Step-by-step explanation:

let a-b,a,a+b be three numbers

sum=39

a-b+a+a+b=39

3a=39

a=13

product=2184

(a-b)(a)(a+b)

(a^2-b^2)(a)=2184

put a=13 in above equation

(169-b^2)(13)=2184

(169-b^2)=168

b=1 or -1

so numbers will be

if b=1

12,13,14

if b=-1

14,13,12