sum of 3 prime numbers is 100 if one of them exceeds another by 36 then one of the number is
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As we know that the sum of three odd numbers cannot be even i.e. one of the prime is even or 2 let one of the other prime is p1 then the third prime is p1+36 now according to question2+p1+p1+36=1002p1=62p1=31Hence, the primes are
2,31,67
2,31,67
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