Question

. Sum of 4 children born at interval of 4 years is 36. What is the age of youngest child?

Answer 1

Question: Sum of 4 children born at interval of 4 years is 36. What is the age of youngest child?

Answer: 3 years

Step by step explanation:

Solution:

Let the age of youngest child be 'x'.

Thus, Age of Second child: x + 4

Age of Third child: x + 8

Age of Fourth child: x + 12

[ Since there's interval of 4 years ]

• Given:

x + (x + 4) + (x + 8) + (x + 12) = 36

4x + 24 = 36

4x = 12

x = 3

Thus, the age of the youngest child is 3 years.

Answer 2

Let the age of youngest child be equal to x

Thus, at an interval of 4 years, the ages of all children will be:

x, x+4, x+8, x+12

Sum is equal to 36

x + x + 4 + x + 8 + x + 12 = 36

=> 4x + 24 = 36

=> 4x = 12

=> x = 3 years

Thus, your answer is 3 years.