Question

sum of 6 consecutive integers is 387

Answer 1

Let the numbers be x,x+1,x+2,x+3,x+4,x+5

their sum is 387

therfore, x+x+1+x+2+x+3 +x+4+x+5=387

6x+15=387

6x=387-15=372

6x=372

x=372/6

x=62

therfore x=62

then ,

x+1=62+1=63

x+2=62+2=64

x+3=62 +3=65

x+4=62 +4=66

x+5=62+5=67

___________________________

Therefore your numbers are 62,63,64,65,66,67☺☺

Answer 2

Given: Sum of 6 consecutive integers is 387.

To find: The numbers.

Answer:

Let one of the numbers be x.

Difference between two consecutive integers = 1 (4 - 3 = 1, 6 - 5 = 1)

Therefore the other 5 numbers will be x + 1, x + 2, x + 3, x + 4 and x + 5.

So, x + x + 1 + x + 2 + x + 3 + x + 4 + x + 5 = 387

6x + 15 = 387

6x = 387 - 15

6x = 372

x = 372/6

x = 62

Therefore the numbers are:

62, 62 + 1 = 63, 62 + 2 = 64, 62 + 3 = 65, 62 + 4 = 66 and 62 + 5 = 67.

Hope it helps :)