Question

Sum of a 2 digit number is nine also nine times this number is twice the number obtained by reversing the order of the digits. find the number

Answer 1

Answer:

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Let the ten's digit no. be x and one's digit no. be y.

So the no. will be = 10x+y.

Given : x+y=9-----(I)

9(10x+y)=2(10y+x)

⇒88x−11y=0 -----(II)

On solving I and II simultaneously you will get x=1 and y=8.

Therefore your no. is 18.