Question

Sum of ages of a and b is 18 and difference is 4. Find the value of (a+b) (a-b).​

Answer 1

Answer:

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HERE IS YOUR ANSWER. . . . . . .

Step-by-step explanation:

.

Sum of ages of a and b = 18

It means (a+b) = 18

Difference of a and b = 4

It means (a-b) = 4

So, (a+b) (a-b)

=> 18×4

=> 72

Answer 2

Answer:

72

Step-by-step explanation:

Sum of a + b = 18 ---- 1

and a - b = 4 ---- 2

Adding eq 2 and 1

(a-b) + (a+b) = 18 + 4

2a = 22

a = 11

Substituting a to find b

a+b = 18

11+b = 18

b = 7

Finding (a+b)(a-b)

Identity 3 → (a+b)(a-b) = a² - b²

(11+7)(11-7)

= 11² - 7²

= 121 - 49

= 72

We can do this the other way too.

(a+b) is given 18

(a-b) is given 4

So (a+b) × (a-b) = 18 × 4

= 72

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