Question

sum of all even numbers from 100to250
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Answer 1

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Step-by-step explanation:

The sum of all even integers from 2 to 250 = 2 + 4 + 6 + 8 + ……… + 250.

This is an Arithmetic Progression with the following parameters:

First Number, a = 2

Last Number, l = 250

Common Difference, d = 2

So, the Number of terms in the Arithmetic Progression, n = (l - a)/d + 1

= (250 - 2)/2 + 1

= 248/2 + 1

= 124 + 1 = 125

So, the sum of the Arithmetic Progression, S = n/2(l + a)

= 125/2(250 + 2)

= 125/2 X 252

= (125 X 252)/2

= 15750

So, the sum of odd integers from 1 to 100 = 15750