Question

sum of all natural numbers between 100&500 which are divisible by 8

Answer 1

first number divisible by 8 and greater than 100 is 104, therefore let a = 104
also, let d = 8
largest number divisible by 8 and less than 500 = 496, now let l = 496
here, no. of terms n = 62
therefore, required no. of natural numbers = 62 - 8 + 1
= 55