in an Ap the sum of first n terms is 3n2/2+13n/2.find the 2nd term
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sn=3n^2/2 +13n/2
s1= 3*1/2 +13*1/2 = 3/2+13/2=16/2=8
s2=3*2^2/2+13*2/2=6+13=19
s3=3*3^2/2+13*3/2=27/2+39/2=66/2=33
first term =a1=s1=8
second term=a2= s2-s1=19-8=11
s1= 3*1/2 +13*1/2 = 3/2+13/2=16/2=8
s2=3*2^2/2+13*2/2=6+13=19
s3=3*3^2/2+13*3/2=27/2+39/2=66/2=33
first term =a1=s1=8
second term=a2= s2-s1=19-8=11
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