Sum of all nos between w 100 and 1000 which are divisible by 5
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Answer:
Step-by-step explanation:
Numbers divisible by 5 from 100 to 1000 are 105,110,.............995
This sequence is an A.P.
Here , first term =a =105
common difference = 5.
We know , a_n = a+(n-1)d
995 = 105+(n-1)5
\Rightarrow \, \, 890 = (n-1)5
\Rightarrow \, \, 178 = (n-1)
\Rightarrow \, \, n=178+1=179
S_n = \frac{n}{2}[2a+(n-1)d]
= \frac{179}{2}[2(105)+(179-1)5]
= \frac{179}{2}[2(105)+178(5)]
= 179\times 550
= 98450
The su
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