Question

sum of all the digits of the number from 1 to 100 is ?
Apply some short tricks

Answer 1

Sum of n natural nos.=n(n+1)/2
By applying this sum of 1st 100 natural nos.is 5050 ,where n is 100

Answer 2

Hey there !!!!!!!!!!

Sum of "n" natural numbers starting from 1 is n(n+1)/2

So, from 1 to 100 there are 100 natural numbers.

So sum of 100 numbers = n(n+1)/2 = 100(100+1)/2 =50*101 = 5050

Hope this helped you..............