Question

Sum of ap whose first term is a and last term is 146 is 7171 value of n

Answer 1

n÷2(a+146) = 7171
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Answer 2

Answer:

$\text{Number of terms are : }\frac{14342}{a+146}$

Step-by-step explanation:

First term of A.P. = a

Last term of A.P = 146

Sum of A.P = 7171

$\text{Sum of A.P is given by formula = } \frac{n}{2}(a\thinspace +\thinspace l),\thinspace \text{( where a is first term and l is last term)}\\\\7171=\frac{n}{2}(a + 146)\\\\14342=n(a+146)\\\\\implies n = \frac{14342}{a+146}$

$\text{Hence, number of terms are : }\frac{14342}{a+146}$