Question

sum of area of two square is 260 m square if the difference of their perimeter is 24 M then find the sides of the two squares​

Answer 1

Let 'A' Be the length of the side of bigger square.

Let 'a' be the lenth of the side of smaller square.

A^2 +a^2 =260 sq.m.........equ.1

4A-4a=24 m

4A =24+4a

A=24+4a/4

A =6+a.........equ.2

Substitute the value of A in equ.1

(6+a)^2+a^2=260 sq.m

36+12a+a^2+a^2=260 sq.m

2a^2+12a+36=260

2a^2+12a+36-260=0

2a^2+12a-224=0

=(a+14)(a-8)=0

length cannot be in negative

Hence a=8

Substitute the value of a in equ.2

A=6+8

A=14

Hence the side of bigger square=14 m

the side of the smaller square=8 m