Question

sum of areas of two square is 468m2 if the difference of their perimeter is 24m. find the sides of two square​

Answer 1

Answer:

Step-by-step explanation:

Let the two numbers be x and y,

Sum of areas of 2 squares = 468m²

x²+y²=468m².............(1)

now,

4x-4y=24m

4(x-y)=24

x-y=6

x=6+y.............(2)

then,

x²+y²=468

(6+y)²+y²=468

36+12y+y²+y²=468

2y²+12y-432=0

2(y²+6y-216)=0

y²+6y-216=0

y²-18y+12y-216=0

y(y-18)+12(y-18)=0

(y-18)(y+12)=0

now,

x=18

and

x=6+y

18-6=y

y=12

                                                 ∴x=18 and y=12