Sum of areas of two squares is 244 cm² and the difference between their perimeter is 8cm. find the ratio of their diagonal.
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Answer:
Ans is 6:5
Step-by-step explanation:
A to q-:
Sum of areas=244cm^2
Let the side of the squares be a1&a2.
a1^2+a2^2=244------(I)
Difference between perimeter=8cm
=>4a1-4a2=8
=>a1-a2=2
=>a1=2+a2------(ii)
Substituting in eqn (I)
(2+a2)^2+a2^2=244
=>4+(a2)^2+4a2+a2^2=244
=>2(a2)^2+4a2-240=0
=>(a2)^2+2a2-120=0-----(iii)
On solving eqn (iii) a2=10cm
Hence a1=12cm
Therefore, ratio of their diagonals =√2a1/√2a2
=a1/a2=12/10=6/5
Hence the ratio is 6:5.
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