Sum of consecutive number from 10 to 20
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Answered by
19
Answer:
155
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Answered by
1
by using sum of n terms formula we can solve this problem
Sn= n/2 [2a+(n-1)d]
here ;n=no of terms
a=first term
d = common difference.
by the problem
n=11
a=10
d=1
By substituting them in the formula we get
S11 = 11/2[2x10+(11-1)1]
= 11/2[20+10]
=11/2[30]
=11x15
=165
so,the sum of consecutive numbers from 10 to 20 is 165
I hope I helped u,if so pls like my ans❤️
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