sum of consecutive odd number between 1 to 15
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Answered by
2
(.5(1+29))²
I realize that you are probably looking at this short expression, and are thinking that this is not a sum, but the result is the same and it is much more compact. It's also much easier to solve. In fact I will show you. So:
1+3= 4
4+5= 9
9+7= 16
16+9= 25
25+11= 36
36+13 =49
49+15= 64
64+17= 81
81+19= 100
100+21= 121
121+23= 144
144+25= 169
169+27= 196
196+29= 225
Or you could arrive at the same answer in the way that I suggested instead.
1+29=30
30÷2=15
15×15=225
Answered by
0
Step-by-step explanation:
sum of consecutive no is=n(n+1)/2
=15×(15+1)/2
15×16÷2
120
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