sum of cubes of first 10 natural numbers
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It seems that the sum is always square, but what is even more remarkable is that the sum of the first n cubes, 13+23+...+ n 3 = ( n ( n +1)/2)2, which is the square of the n th trianglenumber. For example, 13+23+...+103=(10×11/2)2=552 = 3025.
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