Question

Sum of digits of a two digit number is 10. When we interchange the digits, the reverse number is greater than the original number by 18. Find the original number.​

Answer 1

Step-by-step explanation:

let the one place digit be x

then,tens digit 10-x

10(10-x)+x

100-10x+x=100-9x

now,as question said,

10(x)+10-x

10+9x

ATQ

10+9x=100-9x+18

18x=90+18

x=6

original number 100-9×6

46 ansss