Question

Sum of digits of a two-digit
number is 8 if the number
obtained by reversing the digits
is 18 more than the original
number then the original
number is​

Answer 1

Answer:

Let the digit in once place be x

so, the digit in tens place be 8 - x

:. Original no. = 10(8 - x) + 1(x)

= 80 - 10x + x

= 80 - 9x

:. New no. = 10(x) + 1(8-x)

= 10x + 8 - x

= 9x + 8 (By reversing the digits)

According to Question,

New no. - Original no. = 18

= (9x + 8)-(80 - 9x) = 18

= 9x + 8 - 80 + 9x = 18

= 18x -72 = 18

= 18x = 18 + 72(By transposition)

= 18x = 90

= x = 90/18

= x = 5

Required numbers -

Original no. = 80 - 9x = 80 - 9(5)

= 80 - 45 = 35

New no. = 53 (By reversing the digits)

:. The required number is either 35 or 53

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Answer 2

Answer:

hey mate there is an error in question it should be written in question that if the number obtained by reversing the digits is 18 less than the orignal number

Step-by-step explanation:

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