Question

Sum of digits of a two digit number is 8. If the number obtained by reversing the digit is more than the original number by 18, then the original number is

Answer 1

Answer:

Let us assume the digits of a number as 'x' and 'y'. Since it is a 2 digit number, we have one's place and ten's place. ( i.e., The place value of one digit is multiple of 10 and the place value of other digit is one.) I assume you know the difference between place value and face value.

Now going to the problem,

Sum of two digits is 8. => x +y=8→A

Diff between number and its reverse:

=> (10x+y)-(10y+x)=18

=>9x-9y=18

=> x-y=(18/9)=2→B

Solving A and B

x+y=8

x-y=2

=>2x=10=>x=5. Hence y = 3.

Hence the required number is 53