sum of digits of a two digits number is 8 .if their digits are interchanged ,the new number is increased by 18 than the original number. find the original number. (solve this word problem )
Answers
Answer:
The Original Number is 35.
Step-by-step explanation:
Given :
Sum of the digits = 8
The Number with Reversed Digits = 18 more than the original number
To find :
The Original Number
Solution :
- Units Place as x
- Tens Place as 10(8 - x)
10(8 - x) + x
80 - 10x + x
80 - 9x ........ [Original Number]
Number With Reversed Digits -
- Units Place as (8 - x)
- Tens Place as 10(x)
10(x) + (8 - x)
10x + (8 - x)
9x + 8 ....... [Number With Reversed Digits]
The Number with Reversed Digits = 18 more than the original number
★
★ Original Number -
Original Number = 35
The Original Number is 35.
Answer :-
Original number is 35.
Explanation :-
Let the digit at ten's place be x and the digit at unit's place be y
Given
Sum of the digits = 8
⇒ x + y = 8 --eq(2)
Number formed = 10x + y
Number formed when digits are interchanged = 10y + x
Given
Number formed when digits are interchanged = increased by 18 than the Original number
⇒ 10y + x = 10x + y + 18
⇒ - 18 = 10x + y - 10y - x
⇒ - 18 = 9x - 9y
⇒ - 18 = 9(x - y)
⇒ - 18/9 = x - y
⇒ - 2 = x - y
⇒ x - y = - 2 ---eq(1)
Adding eq(1) and eq(2)
⇒ x + y + (x - y) = 8 + (-2)
⇒ x + y + x - y = 8 - 2
⇒ 2x = 6
⇒ x = 6/2
⇒ x = 3
Substitute x = 3 in x + y = 8
⇒ 3 + y = 8
⇒ y = 8 - 3
⇒ y = 5
Number formed = 10x + y = 10(3) + 5 = 30 + 5 = 35
∴ the original number is 35.