Question

sum of digits of two digit number is 8 if 18 is added the number then resultant number is equal to number obtained by reversing the digits of original number find the original number

Answer 1

let digits be x and y

x+y =8(equation 1)

numbers value is 10x+y
so 10x+y+18=10y+x
10x-x+18=10y-y
9x+18=9 y
x+2=y

we finally get x=y-2 (equation 2)
frm eq1

x+y=8
(y-2)+y=8
2y-2=8
y-1=4
y=5.

so x=3

hence the number is 35