Sum of digits of two numbers is 9.If 54 is subtracted from that numbr then the number so formed is same as the number formed by interchanging the digits. Find the numbers.
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Answered by
0
Let the ten's digit be x, then unit's digit is 54−x
and number is 10×x+(54−x)=10x+54−x=9x+54
If digits interchange their places,
number becomes 10×(54−x)+x=540−10x+x=540−9x
540-9x=540-9x
-9x+9x=540-540
0==0
and number is 10×x+(54−x)=10x+54−x=9x+54
If digits interchange their places,
number becomes 10×(54−x)+x=540−10x+x=540−9x
540-9x=540-9x
-9x+9x=540-540
0==0
Answered by
2
let the unit place digit is=x
and tens place digit=y
Hence actual no.=10y+x
Now according to the question
x+y=9-------------1
and
10y+x-54=10x+y
or,9y-9x=54
or, y-x=6------------2
now adding equation 1&2
2y=15
no such no. can possible..
and tens place digit=y
Hence actual no.=10y+x
Now according to the question
x+y=9-------------1
and
10y+x-54=10x+y
or,9y-9x=54
or, y-x=6------------2
now adding equation 1&2
2y=15
no such no. can possible..
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