Math, asked by karthik5939, 1 year ago

Sum of divisors of a number in terms of prime factors

Answers

Answered by rupammtapan

0

Answer:

(a^(p+1) -1)/(a-1) * (b^(q+1) -1)/(b-1) * (c^(e+1) -1)/(c-1) *….

Step-by-step explanation:

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