sum of exponent of prime factors in prime factorisation of 250
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Solution :-
Prime Factorization of 250
______
2 | 250
|_____
5 | 125
|_____
5 | 25
|_____
5 | 5
|_____
| 1
|
Prime factors of 250 = 2 × 5 × 5 × 5
250 = 2¹ × 5³
Sum of the exponents of prime factors in prime factorization of 250 = 1 + 3
= 4
Answer.
Answered by
5
250
= 2 × 125
= 2 × 5 × 5 × 5
= ( 2^1 ) × (5^3)
Sum of exponents
= 1 +3
= 4
I hope this answer helps you
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