Sum of external angles and internal angles of a polygon are equal.
(i)How many sides does that polygon have?
(ii)what is the sum of its internal angles?
Answers
Answered by
12
hey mate..!!!
the answer is
i) 4 sides
ii) 360°
the answer is
i) 4 sides
ii) 360°
Answered by
5
I can try.
let the internal angles be x1,x2,x3........xn
so external angles becomes 360-x1,360-x2,360-x3........360-xn.
ATQ:
x1+x2+......xn=360-x1+360-x2+.....360-xn
sigma(xn)=360n-sigma(xn)
sigma(xn)=180n
x1+x2+......xn=180n....
dont know after this.
let the internal angles be x1,x2,x3........xn
so external angles becomes 360-x1,360-x2,360-x3........360-xn.
ATQ:
x1+x2+......xn=360-x1+360-x2+.....360-xn
sigma(xn)=360n-sigma(xn)
sigma(xn)=180n
x1+x2+......xn=180n....
dont know after this.
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