Sum of first 10 terms of an ap 3,5,7,9 is
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Answer:
a=3
d=5-3=2
n=10
S=n/2[2a+(n-1)d]
S=10/2[2*3+(10-1)2]
S=5[6+9*2]
S=5[6+18]
S=5[24]
S=120
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Answer :- 120
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