Question

sum of first 24th term of A.p 5,8,11,14​

Answer 1

ANSWER:-⤵️⤵️

Here, a=5, d=3, n=24

Sn=n/2[2a+(n-1)d]

Sn=24/2[2(5)+23×3]

Sn=12[10+69]

Sn=12(79)

Sn=948

Sum of 24 terms of this AP is 948

HOPE IT HELPS YOU✌✌✔✔

Answer 2

first term of an A.P is 5= t1=a

d= 3

we know the formula of finding terms

tn=a+(n-1)d

t24=5+(24-1)×3

=5+23×3

=5+69

=74