sum of first 24th term of A.p 5,8,11,14
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Answered by
10
ANSWER:-⤵️⤵️
Here, a=5, d=3, n=24
Sn=n/2[2a+(n-1)d]
Sn=24/2[2(5)+23×3]
Sn=12[10+69]
Sn=12(79)
Sn=948
Sum of 24 terms of this AP is 948
HOPE IT HELPS YOU✌✌✔✔
Here, a=5, d=3, n=24
Sn=n/2[2a+(n-1)d]
Sn=24/2[2(5)+23×3]
Sn=12[10+69]
Sn=12(79)
Sn=948
Sum of 24 terms of this AP is 948
HOPE IT HELPS YOU✌✌✔✔
Answered by
3
first term of an A.P is 5= t1=a
d= 3
we know the formula of finding terms
tn=a+(n-1)d
t24=5+(24-1)×3
=5+23×3
=5+69
=74
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