Math, asked by sampath786, 7 months ago

sum of first 42 integers divisible by 6

Answers

Answered by punamkesharwani17

2

Answer:

mark me as brainlist.......

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Answered by divya509047

6

Answer:

hii the answer is

we know that the first 40 positive integer divisible

by 6,12,18............

this is Ap with a=6 and d=6

s40=20(2(6)+(40-1)+6)=20(12+234)=4290.

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