Sum of first 55 terms in an AP is 3300 , find ots 28 term
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here's the answer to ur question
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n = 28
a = a
d = d
T28 = ?
Tn = a+(n-1)d
T28 = a+(27)d
T28 = a + 27d
Sn = n/2[2a + (n-1)d)
S55 = 55/2[2a + (54)d]
3300 = 55/2[2a+54d]
3300 = 55/2×2[a+27]
3300 = 55[a + 27]
3300 = 55× T28. (cause T28 = a+27d)
3300/55 = T28
60 = T28
so 28 th term is 60
a = a
d = d
T28 = ?
Tn = a+(n-1)d
T28 = a+(27)d
T28 = a + 27d
Sn = n/2[2a + (n-1)d)
S55 = 55/2[2a + (54)d]
3300 = 55/2[2a+54d]
3300 = 55/2×2[a+27]
3300 = 55[a + 27]
3300 = 55× T28. (cause T28 = a+27d)
3300/55 = T28
60 = T28
so 28 th term is 60
Maharaja111:
thank
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