Question

Sum of first 89 multiples of 18

Answer 1

Answer:

1602

Step-by-step explanation:

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Answer 2

$\large \underline{ \underline{\bold{ \: Answer : \: \: \: }}}$

$\to$ The required number is 72090

$\large \underline{ \underline{\bold{ \: Explaination : \: \: \: }}}$

Given ,

First term = 18

Last term = 1602

Number of terms = 89

Common difference = 18

$\huge{ \star}$ Sum of nth term = n/2 ( a + l )

$\to$ Sum = 89/2 ( 18 + 1602)

$\to$ Sum = 89/2 ( 1620 )

$\to$ Sum = 89 × 810

$\to$ Sum = 72090