sum of first even numbers formula given by
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1st even = 2
and common difference = 2
Sn = n/2(2a + (n-1)d)
Sn = n/2(4+ 2n - 2)
Sn = n/2(2+2n)
Sn = n(1+n)
Sn = n²+n
I hope this will be helpful please make it brainliest thank you (@_@)
and common difference = 2
Sn = n/2(2a + (n-1)d)
Sn = n/2(4+ 2n - 2)
Sn = n/2(2+2n)
Sn = n(1+n)
Sn = n²+n
I hope this will be helpful please make it brainliest thank you (@_@)
Gourav2002:
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