Math, asked by Ambikapur678, 10 months ago

sum of first n positive integers

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Answered by Anonymous

Answer :D

s n = n ( n + 1 ) ÷ 2

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Answered by arjun8734

Answer:

sn = n(n+1)/2

Step-by-step explanation:

Let

sn = 1 + 2 +3+......n

a = 1,

last term = n

sn = n(a +l)/2

sn = n(1+n)2

sn = n(n+1)/2

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sum of first n positive integers​

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Answer :D

s n = n ( n + 1 ) ÷ 2

sum of first n positive integers