Question

sum of four consecutive integers is 266what are the integers ​

Answer 1

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HERE IS YOUR ANSWER

Let , the integers be ( x ) , ( x + 1 ) , ( x + 2 ) , ( x + 3 )

ACCORDING TO QUESTION =>

x + ( x + 1 ) + ( x + 2 ) + ( x + 3 ) = 266

4x + 6 = 266

4x = 266 - 6

4x = 260

x = 260/4

x = 65

THEREFORE , THE INTEGERS ARE =>

x = 65

( x + 1 ) = 65 + 1 = 66

( x + 2 ) = 65 + 2 = 67

( x + 3 ) = 65 + 3 = 68.

So , the integers are 65 , 66 , 67 and 68.

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Answer 2

Step-by-step explanation:

First consecutive number is = X

second consecutive number is =( X+1)

third consecutive number is =( X+2)

fourth consecutive number is =( X+3)

(X)+ ( X+1)+(X+2)+(X+3) =266

X+X+X+X+ 1+2+3=266

4x+6=266

4x= 266-6

X=260÷4

X=65

first consecutive number=65

second consecutive number=X+1=65+1=66

third consecutive number=X+2=65+2=67

fourth consecutive number=X+3=65+3=68