Math, asked by anjaliupadhyay141, 2 months ago

Sum of Integral values of 'x' satisfying
(log2x + log, (16x) - 5) (log2x) + (log2x + logx (2x) – 3) (log2x)= 1 is​

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Answered by nandakrish27
1

Answer:

6

Step-by-step explanation:

I think I have considered all possibilities...but of thers something I missed please do point out

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