Question

sum of my digit is 16 and products is 63

Answer 1

Hey... I think this can be ur answer!!

Let the two digits be x and y
ATQ,
x+y =16
x=16-y..(1)

Now,
xy =63
(16-y)y=63
16y-y2=63
0=y2-16y+63
=y2-7y-9y+63
=y(y-7)-9(y-7)
y=7 or y=9
x=16-7=9 or x=16-9=7

Answer 2

Both the digits are 7,9

We can prove this by their sum is 7 + 9 = 16

Their Product is 7 × 9 = 63

Hope that it helped ✌️✌️

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