Question

sum of n term of a GP is ​

Answer 1

Answer:

sum of n terms of a GP

Sn = [a(rⁿ - 1) ] / (r - 1) for | r | > 1

Sn = [a(1 - rⁿ) ] / (1 - r) for | r | < 1

Answer 2

Step-by-step explanation:

Sn in GP

=$\dfrac{a( {r}^{n} - 1)}{r - 1}$