sum of 'n' terms of A•P. 24,21,18, .............. is 108. Find n
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Sn=n/2(2a+(n-1)d)
108=n/2(2*24+(n-1)*-3)
216=n(48-3n+3)
216=n(51-3n)
216=3n(17-n)
72=17n-n^2
n^2-17n+72
n=17+-√289-288/2
=17+-1/2
if n is positive
n=9
if n is negative
n=8
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