Question

sum of present ages of two friends are 23 years, five years ago product of their ages was 42 . find their ages 5 years hence.​

Answer 1

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$\huge\bf\red{Question\::-}$

Sum of present ages of 2 friends are 23 years, five years ago product of their ages was 42. Find their ages 5 years hence.

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$\huge\bf\pink{Solution\::-}$

Let the ages of 2 friends are x and 23 - x

Five years ago product of their ages = 42

➦ (x - 5) (23 - x - 5) = 42

➦ (x - 5) (18 - x) = 42

➦ 18x - x² - 90 + 5x = 42

➦ 23x - x² - 132 = 0

➦ x² - 23x + 132 = 0

➦ (x - 12) (x - 11) = 0

➦ x = 12, x = 11

⛬ Their ages 5 years hence, 17 and 16

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Answer 2

Answer:

$ages \: are \: 17 \: and \: 16$