Question

sum of radius of base and height of solid cylinder is 37m if total surface area of solid cylinde is 1628m find circumference of its base

Answer 1

(r+h)=37m
TSA=1628m²
TSA=2πr(r+h)
=>1628 =2πr(r+h)
=>1628 =circumferecence of base(r+h)
=>1628/37=circumferenceof base
=>circumference =44m

Answer 2

R+H = 37m.....(i)
AND,
TSA(TOTAL SURFACE AREA) =
$2\pi r(r + h)$
SO, A/Q;

$1628 {m}^{2} = 2\pi r(r + h) \\ = > 1628 {m}^{2} = 2 \times \frac{22}{7} \times r \times (37m) \: \: \: \: \: \: \: \: \: \: \: \: (from \: .....(i)) \\ = > \frac{1628 {m}^{2} \times 7 }{2 \times 22 \times 37m} = r \\ = > r = \frac{1628 {m} \times 7 }{2 \times 22 \times 37} \\ = > r = 7m$
NOW, WE KNOW THAT R = 7m
SO, CIRCUMFERENCE OF ITS BASE =
$2\pi r \\ = 2 \times \frac{22}{7} \times 7m \\ = 44m$
THERE YOU GO!!!.....