Question

sum of roots and product of roots 2x^2-6x+3=0

Answer 1

Answer:

$⇒{2x}^{2} -6x+3=0$

$x = \frac{(- (- 6)± \sqrt{( {- (- 6)}^{2} - 4 \times 3 \times 2 } }{2 \times 2}$

$x= \frac{6 ± \sqrt{12} }{4}$

Step-by-step explanation:

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