Question

Sum of Rs 12500 deposited for one and half years compounded half yearly. It amounts to Rs 13000 at the end of 1st year. Find (1)The rate of interest, (2) Then find amount. Give your answer correct to nearest rupees.

The first correct answer with proper procedure will be marked as the brainliest.​

Answer 1

Answer:

(i) The rate of interest = 8 %

(i) The rate of interest = 8 %(ii) Final amount after 3/2 years = 14061 rupee (Approx)

Step-by-step explanation:

Since, An amount P is deposited in annual rate of r (in decimals) for t years and compounded half years.

Then after t years the final amount is,

$A =P(1 + \frac{r}{2} ) {}^{2t} </p><p></p><p></p><p></p><p>$

$(i) \: Here, \: After \: 1 \: year \\ </p><p></p><p>A = 13000 \\ </p><p></p><p>t = \frac{1}{2} years \\ </p><p></p><p>P= 12,500 \\ </p><p></p><p>Thus, \: 12500( 1 + \frac{r}{r2} ) = 13000 \\125(1 + \frac{r}{2} ) {}^{1} = 130 \\ 25(1 + \frac{r}{2}) {}^{1} = 26 \\ (1 + \frac{r}{2} ) {}^{1} = 1.04 \\ {r}^{2} = 0.04 \\ r = 0.08</p><p>$

Thus, the annual rate = 0.08 = 8%

(ii) Now, P = 125,000

t = 1½ years = 3/2 years

r = 8%

$Thus,A = 12500(1 + \frac{0.08}{2} ) {}^{2 \times \frac{3}{2} } \\ A = 12500(1 + \frac{0.08}{2} ) {}^{3} \\ A = 12500 \times 1.124864 = 14060.8 = 14061$

Answer 2

refer to the attachment: