Sum of second even fourth odd and first perfect square after 100 is
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second even after 100 is 104..( 1st even is 102)
fourth odd after 100 is 107(1st is 101,2nd 103,3rd 105)
first perfect square is 121(11²)
so 104+107+122
fourth odd after 100 is 107(1st is 101,2nd 103,3rd 105)
first perfect square is 121(11²)
so 104+107+122
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Answer:
332 is the right answer
Step-by-step explanation:
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